Consider the function $f(x,y)=x^2+2y^2$The maximum value of $f$ on the circle $=x^2+y^2=1$ is:When $f$ attains its maximum value on the circle, $x=$The minimum value of $f$ on the circle $=x^2+y^2=1$ is:<br/>______
Consider the function $f(x,y)=x^2+2y^2$The maximum value of $f$ on the circle $=x^2+y^2=1$ is:When $f$ attains its maximum value on the circle, $x=$The minimum value of $f$ on the circle $=x^2+y^2=1$ is:
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发布时间:2024-09-07 04:02:19