For the function ln ((1 + x) / (1-x)), the correct statement for Taylor power series expansion is:

A、symsx;f=log((1-x)/(1-x)),F2=taylor(f,x,15);;
B、symsx;f=log((1+x)/(1+x)),F2=taylor(f,x,5);;
C、symsx;f=log((1-x)/(1+x)),F2=taylor(f,x,15);;
D、symsx;f=log((1+x)/(1-x)),F2=taylor(f,x,15);